What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3? y−6=1/3(x−2) y+6=1/3(x+2) y−2=1/3(x−6) y+2=1/3(x+6)

The equation of a line in point-slope form is y-6=1/3(x-2) remember point-slope is y1-y2=m(x1-x2)

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.