Select the equation that represents a line with a slope of 3 and that contains the point (-4,2). a) y - 2 = 3(x+4) b) y+2=3(x-4) c) x-4=3(y+4) d)x-4=3(y+2)

A) y - 2 = 3(x+4)

Step-by-step explanation:

Given that the equation is a line with slope =m=3 and

a point on it (x1,y1) = (-4,2)

Any line having slope m and passing through (x1,y1) has equation in point slope form as

y-y1 = m(x-x1)

We are given here x1 =-4, y1 =2 and m =3

y-y1 = y-2 and x-x1 = x-(-4) = x+4

So equation is y-2 = 3(x+4)

Verify:

The line is y = 3x+12+2 = 3x+14

Hence slope =3 is verified

Substitute the point x =-4 and y =2

2 =3(-4)+14 = 2 is true

Thus verified

A is correct option. Equation of line: y-2=3(x+4)

Step-by-step explanation:

Slope of line is 3 and passing point (-4,2).

If slope and passing point given then we have an equation of line

where,

Slope (m)=3

Equation of line:

y-2=3(x+4)

This equation match with option A

Thus. option A is correct.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3