21 points solve the quadratic equation x2 − 4x + 10 = 0 using the quadratic formula. what is the solution when expressed in the form a ± bi, where a and b are real numbers?

Step-by-step explanation:

The correct way to write that "x squared" is x^2.  Thus, you have x^2 - 4x + 10 = 0.

This is a quadratic equation, with a = 1, b = -4 and c = 10.  The discriminant, b^2-4ac, is thus (-4)^2-4(1)(10), or 16 - 40, or -26.

The two solutions are thus:

       -(-4) plus or minus i√26

x =

                     2(1)

or x = (4 + i√26)/2 and x = (4 - i√26)/2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐