Sal has a small bag of candy containing three green candies and two red candies. while waiting for the bus, he ate two candies out of the bag, one after the other, without looking. what is the probability that both candies were the same color? a. 2/5 b. 3/100 c. 8/25 d. 3/5

Option A

Step-by-step explanation:

Given that Sal has a small bag of candy containing three green candies and two red candies.

He ate two candies one after the other.

The probability that both candies were the same color has to be calculated.

The probability that both candies were the same color = P(both are red or both are green)

= P(both are red)+P(both are green)

Total no of ways to draw 2 candies out of 5 = 5C2 = 5(4)/2 = 10

No of ways of drawing 2 red candies = 2C2 =1

No of ways of drawing 2 green candies = 3C2 =3

Hence required prob =(1+3)/10 = 2/5

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00