3(x-3)^2+3 find x-intercepts. solve step by step.

I'll assume this is y=-3(x-3)^2+3

to find the x-intercepts, set y=0 and solve for x:
0=-3(x-3)^2+3
-3=-3(x-3)^2
1=(x-3)^2
+/-1=x-3
+/-1 + 3 = x

x=4, x=2

this makes sense because if you look at the original equation, you see that plugging in these numbers for x, you get 0.

Why you be expecting me to do your math u stupid butt? i ain't gonna but ima get points so you know what i'm sayin boii