Given a line segment with end points a (0,0) and b (6,8), find point c (x, y) that the triangle vertices a, b and c has an area of 25 square units?

C(6.25 , 0)

Step-by-step explanation:

Draw the diagram

A is at (0,0)

B is at (6,8)

Draw a line from A to B.

Put a large dot where (0,6) is. Call this D

Draw BD

Draw another line from (0,0) to just beyond (6,0) Call this C. Draw in BC

What You Have Drawn

The height of the triangle is BD and it is 8. That comes from B which is (6,8)

Solve

Formula

Area = 1/2 * B * H

Area = 25

H = 8

Area = 1/2 B * H

25 = 1/2 * B * 8             Switch sides

1/2  * B * 8 = 25            Combine factors on the left.

4 B = 25                       Divide both sides by 4

4B/4  = 25/4        

B = 6.25

What that means is that AC is 6.25 units long and is on the x axis

C is C(6.25,0)

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

4 and 5)16.97 or 12√2

6)15.59 or 9√3

7)y = 15.59 or 9√3     x =27

8)17.80