Two rectangular adjacent rooms share a wall 1‘ x 1‘ tiles cover the floor of each room describe how the greatest possible length of the adjoining wall is related to the total number of tiles in each room

Consider two adjacent rectangular rooms having Length=L, and, Breadth = B

Now Suppose the wall which is in between two rooms has a height or length =H.

Breadth of wall = B [ if the wall doesn't exceed the breadth of room]

Considering two rooms to be identical,

Area of each room= L × B square unit

Area of each tile = 1×1=1 square unit

Number of tiles required= L B ÷ 1= LB tiles( product of length and breadth of room is number of tiles required)

Suppose if,LB= N

B= N/L  .................(1)

Area of wall(W) = B×H= B H square unit

B =W/H ......................(2)

Equating (1) and (2)

⇒N/L = W/ H

⇒H =

⇒H =

⇒H = W/B

 ⇒  H =

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step-by-step explanation:

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the solution is h=10 because you add 9 to each side of the equation.