Which expression is the completely factored form of x6−64y3 ?

(x^2 - 4y)( x^4 +  4x^2y + 16y^2)

Step-by-step explanation:

x^6−64y^3

- using the identity a^3 - b^3 = (a - b)(a^2 + ab + b^2)  with a = x^2 and b = 4y we have:-

(x^2 - 4y)( x^4 +  4x^2y + 16y^2)

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.