The gross weight of a truck containing 30 pigs is 8 tons 1,123 pounds and 6 ounces. the average weight of one pig is 95 pounds 10 ounces. find the following: a. the net weight of the pigs in the truck. b. the weight of the empty truck.

Step-by-step explanation:

a) There are 16 ounces in a pound, so 10 ounces is 10/16 = 5/8 lb. The total weight of the pigs is their number multiplied by their average weight:

... weight of pigs = 30 × 95 5/8 lb = ((30·95) + (30·5/8)) lb

... = (2850 + 150/8) lb = (2850 +18 3/4) lb = 2868 lb 12 oz

b) The truck tare weight is the gross weight less the weight of the pigs.

... truck tare = truck gross - truck load

... = (8×2000 lb) + (1123 lb) + (6/16 lb) - (2868 3/4 lb)

... = 17123 3/8 lb - 2868 3/4 lb = (17123 -2868) lb +(3/8 -3/4) lb

... = 14255 lb - 3/8 lb

... = 14254 5/8 lb

... = 14000 lb + 254 lb + 5/8 lb

... truck tare weight = 7 tons 254 lbs 10 oz

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Many graphing calculators will handle calculations with fractions very nicely.

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: