An ice-hockey puck is slid along ice in a straight line. the puck travels at a steady speed of 20 ms^-1 and experiences no frictional force. how far does the puck travel in 2.5 s? a. 5 m b. 8 m c. 25 m d. 50 m

d. 50 m

Step-by-step explanation:

1. You have the following information given in the problem above:

- The speed of the puck is 20 and experiences no frictional force.

- The time is 2.5 seconds.

2. Then, to calculate the distance, you must apply the following formula:

Where is the distance, is the speed and is the time.

3. Now, you must substitute values into the formula, as below:

4. Therefore, the result is:

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answer: d.) the total number of protons and neutrons is 15

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