Will mark brainliest

1. solve the inequality & graph the solution: v-6≥4

2. solve the inequality & graph the solution: -5x< 15

3. solve the inequality & graph the solution: 3k> 5k+12

5. solve the compound inequality: 2t≤-4 or 7t≥49

6. solve the equation. if there is no solution, write no solution (show work): |n+2|=4

7. solve the equation. if there is no solution, write no solution (show work): |2x-7|> 1

8. given a={1,2,3,4,5,6,7,8,9} & b={2,4,6,8}, what is aub ( the u is that one weird u like symbol)

9. draw a venn diagram to represent the intersection & union of the sets: p={1,5,7,9,13}, r={1,2,3,4,5,6,7}, & q={1,3,5}

1)

v - 6 ≥ 4

  +6   +6

v      ≥ 10

Graph: 10 -----------------→  the dot at 10 is filled in because of the "equal to" symbol

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2)

-5x < 15

 divided by a negative so the symbol flipped

x > -3

Graph: -3 o------------------→ the dot at -3 is NOT filled in because it's NOT "equal to"

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3)

3k > 5k + 12

-5k  -5k      

-2k >          12

  divided by a negative so the symbol flipped

k < -6

Graph: ←------------o -6   the dot at -6 is NOT filled in because it's NOT "equal to"

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5)

2t ≤ 4      or    7t ≥ 49

     or    

 t ≤ 2      or      t ≥ 7

Graph: ←------- 2        7 ---------→   the dots at 2 and 7 are filled in

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6)

| n + 2 | = 4

n + 2 = 4      or     n + 2 = -4

    -2   -2                 -2   -2

n      = 2        or     n       = -6

n = {2, -6}

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7)

| 2x - 7 | > 1

2x - 7 > 1       or     2x - 7 < -1

     +7  +7                 +7   +7

2x      > 8       or     2x     <  6

                or      

    x > 4          or         x < 3

Graph: ←----------o 3      4 o------------→

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8)

A = {1, 2, 3, 4, 5, 6, 7, 8, 9}    B = {2, 4, 6, 8}

A U B = {1, 2, 3, 4, 5, 6, 7, 8, 9}    union combines both sets

A ∩ B =  {2, 4, 6, 8}   intersection includes only those that are in BOTH sets

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9)

P = {1, 5, 7, 9, 13}   R = { 1, 2, 3, 4, 5, 6, 7}    Q = {1, 3, 5}

P ∩ R ∩ Q = {1, 5}

P ∩ R = {7}  disregard 1 & 5 since they are already in P∩Q∩R

R ∩ Q = {3}  disregard 1 & 5 since they are already in P∩Q∩R

P ∩ Q = { }  disregard 1 & 5 since they are already in P∩Q∩R

P no intersection = {9, 13)

R no intersection = {2, 4, 6}

Q no intersection = {  }

If you can't figure out how to draw it based on the information I provided, please see the attached diagram. Note: Usially, you would only identify P, Q, R.  I identified the intersections so you would understand why those specific numbers are placed in the designated sections.

muyb ajo

step-by-step explanation:

jegosu

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.