Me a minor league baseball team plays 109 games in a season. if the team won 13 more than three times as many games they lost, how many wins and loses did the team have?

Let losses = X

They won 13 more than 3 times as many so wins =  3X +13

Now you have wins  + loses  = total games:

X +3X + 13= 109

Combine like terms:

4x + 13 = 109

Subtract 13 from each side:

4x = 96

Divide each side by 4:

x = 96 / 4

X = 24

Wins = 3X +13

3(24) +13 = 72+13 = 85

Wins = 85 games

Losses = 24 games

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz