Atruck can be rented from company a for 130 dollars a day plus .30 per mile. company b charges 60 dollars a day plus .50 per mile to rent the same truck. find the number of likes in a day at witch the rental costs for both companies are the same

We know that Company B will be less expensive at first, but Company A will become a better option as the miles rack up. Eventually, Company A will be less expensive. There will be a point where the price will be the same for each company.  

150 + .20x = Company A

70 + .40x = Company B

If we set these two equations equal to each other, we find out when the price will be the same.

150 + .20x = 70 + .40x

If we solve for x, we find out how many miles must be driven in a day to make the rental cost the same. After that, Company A will be a better deal.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.