For g(x) = 4x-9 find g(x) when x=3 and when x=5 i need again i don't get this one either!

Hey there!

Let's first solve g(x) when x = 3.

The first step is to change wherever it says x in the equation to 3, because that is the value we are solving for.

g(3) = 4(3) - 9

Next, we can multiply 4 by 3, because multiplication comes before subtraction in PEMDAS.

g(3) = 12 - 9

Lastly, we can subtract 9 from 12 to get the final value.

g(3) = 3   So, the value for g(x) when x = 3 is 3.

Now, we'll solve for g(x) when x = 5.

The first step is to change wherever it says x in the equation to 5, because that is the value we are solving for.

g(5) = 4(5) - 9

Next, we can multiply 4 by 5, because multiplication comes before subtraction in PEMDAS.

g(5) = 20 - 9

Lastly, we can subtract 9 from 20 to get the final value.

g(5) = 11   So, the value for g(x) when x = 5 is 11.

Hope this helps!

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: