Knowing that p(n)= 2n^4+4n^3 -6n^2 what r the n roots

by the distributive property of all reals, we have that

p(n) = 2n^2(n^2 + 2n - 3)

by virtue of factoring, it is true that p(n) = 2n^2(n+3)(n-1).

should we want p(n) = 0, we know that at least one of 2, n^2, n+3, or n-1 needs to be zero by the zero factor property. 0 times anything is zero.

so the answer is n = 0, n = -3, and n = 1 as the roots because those are the values of n for which p(n) is 0.

is only a line? i think so