The first , second, and the nth terms of an arithmetic sequence are 2,6, and 58 respectively find the value of n

n = 15

the nth term of an arithmetic sequence is = a₁ + (n-1)d

where d is the common difference

d = a₂ - a₁ = 6 - 2 = 4

= 2 + 4n - 4 = 58

4n - 2 = 58

4n = 60 ( divide both sides by 4 )

n = 15

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it