What is the sum of an infinite geometric series if the first term is 81 and the common ratio is 2⁄3? a. 567 b. 135 c. 243 d. 729

C

the sum to infinity of a geometric series  =

where a is the first term and r the common ratio

= = 81 × 3 = 243

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

answer: i guess 105 degrees?

step-by-step explanation: