Point a has an x coordinate of −2 and lies in a circle with a center at (0, 0) and a radius of 5. to the nearest tenth, what is the y-coordinate for point a?

hello,

my name is papa guy i am give verified answer and here just might be one.

the equation of a circle whose center is (h,k) and radius is r is given by:

(x-h)^2+(y-k)^2=r^2

given that center is (0,0) and r =8 and x=7

putting all the values: -

(7–0)^2+(y-0)^2=64

49+y^2 =64

y^2=15

y=+ sqrt(15) [rejected] or y= -sqrt(15)

given in the question is that point a is below the x axis

hence y=-sqrt(15)

=-3.87

you.

not if i am wrong it just might be my fault i haven't done math like this since 8th grade. i am now on my way to collage

answer: b) 4.6

just took test

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2