Write an equation for the linebacker through the point (6,5) with slope -7 in point slope form y=y0+m(x-x0)

y - 5 = -7(x - 6)

the equation of a line in ' point- slope form ' is

y - b = m(x - a )

where m is the slope and (a, b) a point on the line

here m = - 7 and (a, b ) = (6, 5 )

y - 5 = - 7(x - 6 ) ← in point- slope form

idk

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)