Nour drove from the dead sea up to amman, and her altitude increased at a constant rate. when she began driving, her altitude was 400meters below sea level. when she arrived in amman 2 hours later, her altitude was 1000 meters above sea level. let a(t), left parenthesis, t, right parenthesis denote nour's altitude relative to sea level a (measured in meters) as a function of time t (measured in hours).

a(t) = 700t-400

Step-by-step explanation:

Given that when Nour drove altitude increased at a constant rate. Let us consider sea level as 0 and starting time as 0 we have

At the start t =0 and a = -400 m

When t=2   a = 1000 m.

Rate of change of a wrt time = change in a/Change in time

= {1000-(-400)}/(2-0) = 700

i.e. slope = 700

a = 700 t +C

To find C:

When t =0, a =-400

Hence C =-400

Equation is a(t) = 700t-400

i believe that the slope of the line is -5

step-by-step explanation:

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1