Write an equation of the parabola in intercept form with x-intercepts of 12 and -6; and an axis of symmetry of (14, 4). show work!

Intercept form is: y = a(x - p)(x - q)  

It is given that:  p = 14, q = -6, x = 14, y = 4

4 = a(14 - 12)(14 - (-6))

4 = a(2)(20)

4 = 40a

y = (x - 14)(x + 6)

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.

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