Two number cubes are rolled for two separate events: event a is the event that the sum of numbers on both cubes is less than 10. event b is the event that the sum of numbers on both cubes is a multiple of 3. complete the conditional-probability formula for event b given that event a occurs first by writing a and b in the blanks: a0 | a1) = a2 ∩ ) a4) if someone could comment cant figure this question out

Step-by-step explanation:

Since we have given that

A: getting the sum of number on both cubes is less than 10

B: getting the sum of numbers on both cubes is a multiple of 3

Conditional probability for event B given that A occurs first :

A ={(1,1)(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(5,1)(5,2),(5,3),(5,4),(6,1)(6,2)(6,3)}

B={(1,2),(2,1),(4,2)(2,4),(3,3),(5,4)(4,5),(3,6),(6,3)}

and

and

So using the formula,