Line segment of length k is divided into 3 equal parts. what is distance between midpoints of first and third segments? a) 2k/3 b) k c) k/6 d) 2k

k is divided into 3 equal parts: 0 to k/3, k/3 to 2k/3 and 2k/3 to k.

midpoint of first segment = (0+k/3)/2 = k/6

midpoint of third segment = (2k/3+k)/2 = 5k/6

distance in between = 5k/6-k/6 = 2k/3

The answer is A).

answer: this is not a question

step-by-step explanation: this is a answer

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).