How many different ways can the letters of " accommodate" be arranged?

2,494,800

Step-by-step explanation:

"Accommodate" has n = 11 letters.

Without repeated letters the answer would be 11! = 39,916,800.

But there are 4 letters repeated twice, these are: (a, c, o, m).

Then the solution is to divide 11! by 2! multiplied 4 times to compensate for duplications, that is:

          11!              39,916,800        39,916,800

X = =   = = 2,494,800

      2! 2! 2! 2!       2 . 2 . 2 . 2               16

Then, the letters of ​"accommodate​" can be​ arranged of 2,494,800 different ways

step-by-step explanation: i dont