If (3,n) is a solution of ax+3y=6 and (n,5) is a solution of 5x+y=20,what is the value of a?

We have 3A + 3n = 6 and 5n + 5 = 20;

Then, 5n = 15;

n = 3;

Finally, 3A + 9 = 6;

3A = -3;

A = -1;

answer: 7270

step-by-step explanation:

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option