Which rule transforms quadrilateral abcd to quadrilateral a'b'c'd'? a. (x,> (x,-y-4) b. (x,> (x+6,-y) c. (x,> (x+6,y-4) d. (x,> (-x, y-4)

The rule transforms the quadrilateral ABCD to quadrilateral A'B'C'D' is given by

D.(-x,y-4).

Step-by-step explanation:

Given quadrilateral ABCD  transform into new quadrilateral A'B'C'D.

The transformation is a  special rule by which to determine the coordintae of  image point of any coordinate of given point . The transformation can be rotation, reflection, dialtion etc.

In given figure of qudrilateral ABCD

Coordinate of A (-5,4)

Coordinate of B(0,1)

Coordinate of C (-4,0)

Coordinate of D (-6,2)

In II figure  of quadrilateral A'B'C'D

Coordinate of A' (5,0)

Coordinate of B' (0,-3)

Coordinate of C' (4,-4)

Coordinate of D' (6,-2)

Then we can see that coordinate of A (-5,4) change into A' (5,0)

It means x change into -x and y change into y-4

Similarly in same  way  B (0,1) change into B'(0,-3)

C(-4,0) change into C'(4,-4)  and D( -6,2) change into D'(6,-2)

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!