The length of the segment ad is 28 cm. the distance between the midpoints of segments ab and cd is 16 cm. find the length of the segment bc .

BC=4 cm

Step-by-step explanation:

Please refer to the image attached to this. AD is a line segment which 28 cm long. E and F are the mid point of AB and CD which are separated by a distance of 16 cm

If we say that AE=EB=x and CF=FD=y

it clear from the figure that

2x+BC+2y=28

2(x+y)+BC=28

EF=16

Hence

x+16+y=28

x+y=12

There for

2(x+y)+BC=28

2*12+BC=28

24+BC=28

BC=4cm

heudhduxhdnshenebdutbbt

step-by-step explanation:

hrhhdhdbbrurb ees

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week