Simplify the expression: (2 x^2 y^5)(3 x^3 y^3) a) 6 x2/3 y5/3 b) 6 x-1 y 2 c) 6 x6 y15 d) 6 x5 y8

(2x²y⁵)(3x³y³)

Multiply the coefficients and add the exponents.

2 * 3 = 6

x² * x³ = x²⁺³ = x⁵

y⁵ * y³ = y⁵⁺³ = y⁸

Put it all together for you answer, 6x⁵y⁸, option D

it’s supposed to be -4+45=41

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺