The sum of six times a number and nine is equal to the difference of the number and eleven. find the number. round your answer to the nearest integer, if necessary.

Suppose the number in this case to be n.

According to the statement given, six times of number would be 6n

and

the sum of 6 times the number (6n) and nine would be ---> 6n + 9

is equal to the difference of the number (6n) and eleven ---> n - 11.

So, the final equation becomes:

6n + 9 = n - 11

Solving this, place both the values of n on one side and the numbers on the other side but do not forget to change the sign of the value that you change the side of.

6n - n = -11 -9 (here we changed the signs of positive n to -n and positive 9 to -9 because we changed their sides)

5n = -20

n = -20/5

n = -4

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong