Find the value of b so that 4x^2+bx+9 has a factor of 2x-3

          2x - 3          

2x - 3 (4x² + bx + 9

        - (4x² - 6x)

               (b + 6)x  + 9

            -      (-6x   + 9)      

(b + 6)x - (-6x) = 0    it must equal zero if 2x - 3 is a factor  

bx + 6x + 6x = 0

bx + 12x = 0

        bx = -12x    

          b  = -12

b = -12

You can check by multiplying (2x - 3) the factor given and (2x - 3) the factor found when dividing by the given factor.

(2x - 3)(2x - 3) = 4x² -12x + 9

step-by-step explanation:

if u want da anser kill your teeser ifu hav wun

i dont know the answer but here's a picture of a dog