Mathematics, 08.07.2019 07:30 indya2

Vera wants to graph a line that passes through (0, 2) and has a slope of . which points could vera use to graph the line? check all that apply. (–3, 0) (–2, –3) (2, 5) (3, 4) (6, 6)

Answers: 2

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Answer from: lilmackey

we have

1) The line passes through (0,2)

2) The slope is equal to $\frac{2}{3}$

we know that

If a point lies on the graph of the line, then the point must satisfy the equation of the line

Step 1

Find the equation of the line

we know that

the equation of the line in point-slope form is equal to

y-y1=m*(x-x1)

we have

(x1,y1)=(0,2)

$m=\frac{2}{3}$

substitute in the equation

$y-2=\frac{2}{3}*(x-0)$

$y=\frac{2}{3}x+2$

we will proceed to verify each of the points to determine the solution of the problem

If a point lies on the graph of the line, then the point must satisfy the equation of the line and the equation will be true for the point

Step 2

Point (-3,0)

Substitute the value of x and y in the equation of the line

$0=\frac{2}{3}*(-3)+2$

0=-2+2

0=0 -------> is true

therefore

the point (-3,0) lies on the line

Step 3

Point (-2,-3)

Substitute the value of x and y in the equation of the line

$-3=\frac{2}{3}*(-2)+2$

$-3=-\frac{4}{3}+2$

$-3=\frac{2}{3}$ ------> is false

therefore

the point (-2,-3) not lies on the line

Step 4

Point (2,5)

Substitute the value of x and y in the equation of the line

$5=\frac{2}{3}*(2)+2$

$5=\frac{4}{3}+2$

$5=\frac{10}{3}$ ------> is false

therefore

the point (2,5) not lies on the line

Step 5

Point (3,4)

Substitute the value of x and y in the equation of the line

$4=\frac{2}{3}*(3)+2$

4=2+2

4=4 ------> is True

therefore

the point (3,4) lies on the line

Step 6

Point (6,6)

Substitute the value of x and y in the equation of the line

$6=\frac{2}{3}*(6)+2$

6=4+2

6=6 ------> is True

therefore

the point (6,6) lies on the line

therefore

the answer is

Vera could use the points

the point (-3,0)

the point (3,4)

the point (6,6)

using a graphing tool

see the attached figure to better understand the problem

Vera wants to graph a line that passes through (0, 2) and has a slope of . which points could vera u

Answer from: Quest

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

= $\sqrt{(9-6)^{2} +(12-6)^{2} } \\=\sqrt(45)=3\sqrt(5)$

side j'k'=distance between j' and k'

= $\sqrt{(3-2)^{2} +(2-4)^{2} } \\=sqrt(5)$

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

Answer from: Quest

step-by-step explanation:

idk

i know the way

and

idk

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