What is the absolute value of –38? a. 19 b. –19 c. 38 d. –38

Answer

C. 38

Explanation

The absolute value of any digit is the magnitude or its size. The negative side is not considered.

It can also be defined as the actual magnitude of a numerical value or measurement, irrespective of its relation to other values.

It is represented as; /x/.

The absolute value of -38 is /-38/.

∴ /-38/ = 38

∞ this is your sign

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15