What is the solution to x+y-z=1 x+2z=0 2x+2y=4

EQ. 1: x+y-z = 1

EQ 2: x +2z =0

EQ. 3: 2x+2y=4

Solve for X in EQ. 2: x +2z=0, subtract 2Z from each side:

x = -2Z

Replace X in EQ. 1 with solution of EQ 2 and solve for Y:

-2z + y -z =1

Simplify:

-3z +y = 1

Add 3z to each side::

y =3z +1

Replace X and Y in EQ.3 and solve for Z:

2(-2z) +2(3z+1) = 4

Distributive property:

-4z + 6z +2 = 4

Simplify:

2z +2 = 4

Subtract 2 from each side:

2z = 2

Divide both sides by 2:

z = 1

Now replace z with 1 and solve:

X = -2z = -2(1) = -2

Y = 3z +1 = 3(1) +1 = 3+1 = 4

Z = 1

Solution is (-2,4,1)

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.