Whats the axis of symmentry for f(x)=-2(x-2)squared-4

f(x)=-2(x-2)squared-4 => f(x)=-2(x-2)^2 - 4  =>  2(x^2-4x+4) - 4

This becomes f(x) = 2x^2 - 8x + 8 - 4.

This being a quadratic, a = 2, b = -8 and c = 4.

Theformula for the axis of symmetry is x = -b/(2a).  Here, that comes to:

x = -(-8) / (2*2) = 8/4 = 2

The axis of symmetry here is the vertical line x = 2.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

ok then what happened.