Find 3 consecutive even integers such that the sum of the smaller 2 is 6 less than twice the largest one

n, n + 2, n + 4 - three consecutive even integers

n + 2 = 2(n + 4) - 6     |use distributive property

n + 2 = (2)(n) + (2)(4) - 6

n + 2 = 2n + 8 - 6

n + 2 = 2n + 2     |subtract 2 from both sides

n = 2n       |subtract 2n from both sides

-n = 0

n = 0

n + 2 = 0 + 2 = 2

n + 4 = 0 + 4 = 4

0, 2, 4.

false

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