Find three consecutive integers whose sum is -33

n, n + 1, n + 2 - three consecutive integers

-33 - the sum

Equation:

n + (n + 1) + (n + 2) = -33

n + n + 1 + n + 2 = -33

3n + 3 = -33      |subtract 3 from both sides

3n = -36    |divide both sides by 3

n = -12

n + 1 = -12 + 1 = -11

n + 2 = -12 + 2 = -10

-12, -11, -10.

answer: ouch. thats difficult

step-by-step explanation:

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: