An object is launched from a platform. it's height (in meters), x seconds after the launch, is modeled by: h(x)=-5(x-4)^2+180. what is the height of the object at the time if launch?

The height of the object at the time of launch is 100 meters.

To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)

h(x)=-5(x-4)^2+180

h(0)=-5(0-4)^2+180

h(0)=-5(-4)^2+180

h(0)=-5(16)+180

h(0)=-80+180

h(0) = 100

100

Step-by-step explanation:

Cause I just did this problem and don't feel like explaining

i dont understand the question? ?

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: