3bouquets of flowers are ordered at the florist. 3 roses 2 carnations and 1 tulip costs $14, 2 carnations and 6 tulips costs $38, and 1 rose 12 carnations and 1 tulip costs $18. how much does each item costs?

The correct answer is : Rose cost is 2.1$,

                                       carnation cost is 0.82$ and

                                        tulip cost is 6.06$

Solution:-

Let rose cost be r$, carnation cost be c$ and tulip cost be t$.

Given 3 roses,2 carnations and 1 tulip costs 14$.

That is 3r+2c+t = 14, let it be first equation.

Also given 2 carnations and 6 tulips costs 38$.

That is 2c+6t=38

           c+3t=19

            c=19-3t

Also 1 rose, 12 carnations and 1 tulip costs 18$.

That is r+12c+t=18

Let us plugin c=19-3t in above equation.

           r+12(19-3t)+t = 18

            r=35t-210

Let us plugin r and c in first equation.

3(35t-210)+2(19-3t)+t =14

105t-630+38-6t+t =14

100t = 606

  t=6.06$

c=19-3*6.06 = 0.82$

r=35*6.06-210=2.1$

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

300pi

step-by-step explanation: