Which is a possible turning point for the continuous function f(x)? (–2, 0) (0, –2) (2, –1) (4, 0)

We are given coordinates of a continuous function f(x)

(–2, 0)

(0, –2)

(2, –1)

(4, 0).

We need to find the possible turning point for the continuous function.

Note: Turning point is a point on the graph where slope of the curve changes from negative to positive or positive to negative.

A turning point is always lowest or highest point of the curve (where bump of the graph seen).

For the given coordinates we can see that  (–2, 0) and (4, 0) coordinates are in a same line, that is on the x-axis.

But the coordinate  (0, –2) is the lowest point on the graph.

Therefore, (0, –2) is the turning point for the continuous function given.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~