There are two cables coming off the top of a building from the same point. each cable is secured to the ground. the longest cable is 200 ft. it is attached at point m and creates a 32° angle of elevation with the ground. the other cable is attached at point n. if the angle formed between the two cables at the top of the building is 25°, what is the distance between points m and n? measure of ð n = °

Call the point of attachment at the top of the building point T. (Angle T = 25°) The angle N = 180° -32° -25° = 123°. The Law of Sines tells you the relationship ...

... TM/sin(N) = MN/sin(T)

... MN = TM·sin(T)/sin(N) = (200 ft)·sin(25°)/sin(123°)

... MN ≈ 100.8 ft

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1