Kyra has a rock collection. when she puts her rocks into 2 equal piles, there are no rocks left over. when she puts her rocks into 3 equal piles ,there are still no rocks left over .when she puts her rocks into 4 equal piles there are still no rocks left over. how many rocks could kyra have?

any multiple of 12

Since 2, 3 and 4 divide exactly into the number of rocks

We are looking for the common multiples of 2, 3 and 4

2 × 3 × 4 = 24 is possible but dividing by 2 gives 12 the lowest common multiple

Any multiple of 12 gives a possible number of rocks.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

step-by-step explanation: