How large is the acceleration of a 60 kg runner if the friction between her shoes and the pavement is 500 n?

The force of friction is given in the scenario:

Force = 500 Newton

and the mass of the runner  is 60 kg

To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:

Where 'F' represents the force, 'm' represents the mass, and 'a' represents the acceleration.

Plugging the value of variables we get:

Solving for 'a' (acceleration) we get:

Newton/kilogram or meters/ second squared

So the acceleration of the runner is 8.33 meters/ second squared.

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !