There is a line that includes the point (6,9) and has a slope of 1. what is it’s equation in slope-intercept form?

The line passes through (6,9)

The slope is 1

Take a second point (x,y) along the line;

Slope = Change in y-axis divide by change in x-axis

(y - 9)/(x - 6) = 1

y - 9 = x - 6

y = x + 3

The equation in slope-intercept form is;

y = x + 3

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

mark brainliest!