Bis the midpoint of ac; ab = 9x+1, bc=2x+15

Question:

B is the midpoint of ac; ab = 9x + 1, bc = 2x + 15

To find ac you have to make into this form of equation:

9x + 1 = 2x + 15

Steps:

1. Subtract 1 from both sides:

2. Simplify,

3. Then, subtract 2x from both sides

4. Simplify,

5. Then, divide both sides by 7

6. Simplify,

So to find ac plug 2 in the x

9(2) + 1 + 2(2) + 15

7. Simplify,

Hope that helped!!!

~Serina

AB = BC since B is the midpoint

9x + 1 = 2x + 15

7x = 14

x = 2

AC = 9(2) + 1 + 2(2) + 15 = 19 + 19 = 38 units.

its 4 because 2 times 2 is 4, if you double the number two you get four

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet