Find the max value of c=6x-2y subject to the following constraints: x≥0 y≥0 x+2y≤14 4x-y≤20

Graph the equations or solve the system of equations to find the vertices within the shaded region.

x≥0, y≥0 represents the first quadrant.

x + 2y ≤ 14   ⇒  has intercepts (14, 0) and (0, 7).

4x - y ≤ 20  ; has intercepts (5, 0) and (-20, 0). Disregard (-20, 0) since it is not in Quadrant 1.

x + 2y ≤ 14 and 4x - y ≤ 20 intercept at (6,4).

Now evaluate the value (C) at the intercepts (0, 7), (5, 0), and (6,4).  Note: (14, 0) has been disregarded because it is outside of the shaded region.

C = 6x - 2y at (0, 7)  ⇒ C = 6(0) - 2(7)  ⇒  C = 0 - 14   ⇒  C = -14

C = 6x - 2y at (5, 0)  ⇒ C = 6(5) - 2(0)  ⇒  C = 30 - 0   ⇒ C = 30

C = 6x - 2y at (14, 0)  ⇒ C = 6(6) - 2(4)  ⇒  C = 36 - 8   ⇒  C = 28

The maximum value (C)  equals 30

maximum value is 30

the answer for this question is : 360°

step-by-step explanation:

we have been given a triangle   we need to tell which one of these is a triangle below to map onto itself.

360° rotation is the complete rotation which eventually leads to the same figure which is given.

the correct will be, that is 360° that will cause the triangle below to map onto itself.