Tim is buying paper cups and plates. cups come in a package of 12 and plates come in a package of 10. he must buy the same number of cups ans plates, but with the least number of packages. if a package of cups is $3 and a package of plates is $5, how much money did tim spend all together?

Tim would spend 88 dollars on cups and plates becaus since 12x5 is 60 and 10x6 is 60 then that gets you to the same amount of cups and plates. so you would add 3 plus 5 together to get 8 and then 6 plus 5 togeher to get 11 and then you muliply those toether to get how mcuh he would ahve to spend.

Hope this helps :)

nope.   happens to me as well.

-aparri

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: