What are the solutions to the equation? x3+3x2−4x−12=0 enter your answers in the boxes. x= x= x=

So with this, we are going to be factoring by grouping. Firstly, factor x³ + 3x² and -4x - 12 separately. Make sure that they have the same quantity on the inside:

Now you can rewrite this equation as . However we are not finished yet.

With x² - 4, we will be applying the difference of squares, which is "(x² - y²) = (x + y)(x - y)". Apply this here as such:

Now apply the zero product property and solve for x:

Your answers are x = -2, x = 2, and x = -3.

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