The coordinates of the vertices of △abc are a(−2,2), b(5,−3), and c(−4,−1). identify the perimeter of △abc. round each side length to the nearest tenth before adding. ! answers: 21.4 30.9 10.7

the distance from (-2,2) to (5,-3) is 8.6,

(5,-3) to (-4,-1) is 9.2

(-4,-1) to (-2,2) is 3.6

8.6+9.2+3.6= 21.4

so the perimeter is 21.4

21.4

Step-by-step explanation:

Given: The coordinates of the vertices of △ABC are A(−2,2), B(5,−3), and C(−4,−1).

To find: Identify the perimeter of △ABC. Round each side length to the nearest tenth.

Solution: To find the perimeter of △ABC, we first need to find the length AB, BC and AC.

We know the distance formula between the coordinates is

Now, rounding each side to the nearest tenth we have,

Now, perimeter of △ABC

Hence, perimeter of △ABC is 21.4.

a. 3/4 ÷ 1/8 = 6

step-by-step explanation:

in the question, the number line represents 3/4 divided into 6 equal units. each arrow represents a unit and there are a total of six arrows.

the size of each unit is 1/8 as shown.

showing that 1/8 divides 3/4 into 6 divisions:

3/4 ÷ 1/8

= 3/4 x 8/1

= 3/1 x 8/4

= 3 x 2

= 6

hence, the number line represents six divisions given by 3/4 ÷ 1/8.

why can't you?

step-by-step explanation: