Suppose that the distance an aircraft travels along a runway before takeoff is given by upper d equals left parenthesis 5 divided by 3 right parenthesis t squaredd=(5/3)t2, where d is measured in meters from the starting point and t is measured in seconds from the time the brakes are released. the aircraft will become airborne when its speed reaches 480480 km divided by hkm/h. how long will it take to become airborne, and what distance will it travel in that time?

The aircraft will take 40 seconds to become airborne and it will travel 2666.666.... meters in that time.

Explanation

The distance an aircraft travels along a runway before takeoff is given by.....

, where is in meters and is in seconds.

The aircraft will become airborne when its speed reaches 480 km/h. So first we need to convert this 480 km/h into meter/second.

Now for finding the time taken by the aircraft to become airborne, we need to find the value of when  

The given equation is:  

Taking derivative both sides with respect to , we will get ......

So, the aircraft will take 40 seconds to become airborne.

Now, the distance traveled in that time will be:   meters.  

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐