The parents’ club has $2,500 to invest in printed shirts to sell at their fundraiser. what is the maximum number of shirts that they can buy? quantity; 101-150 / 151-200 / over 200 price per shirt; $18 / $15 / $11

Total amount to be invested = $2,500.

First given price for a printed shirt = $18.

Number of shirts that they can buy = Total money ÷ Price of each shirt.

a)  For unit price $18 number of shirts can buy = 2,500/18 = 138.89, so approximately 138 ( because it's less than 139).

Therefore, with unit price $18 the maximum number of shirts can buy = 138 shirts.

a)  For unit price $15 number of shirts can buy = 2,500/15 = 166.67, so approximately 166 ( because it's less than 167).

Therefore, with unit price $15 the maximum number of shirts can buy = 167 shirts.

a)  For unit price $11 number of shirts can buy = 2,500/11 = 227.27, so approximately 227 ( because it's less than 228).

Therefore, with unit price $11 the maximum number of shirts can buy =227 shirts.

Therefore, with least unit price $11 , maximum number of shirts could be buy and that is 227 shirts which is over 200.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17